Processing math: 100%

donderdag 5 december 2019

Goniometrie

a+b+c=πa+b=πctan(a+b)=tan(πc)tan(a)+tan(b)1tan(a)tan(b)=tan(c)tan(a)+tan(b)=tan(c)(1tan(a)tan(b))tan(a)+tan(b)=tan(c)+tan(a)tan(b)tan(c)tan(a)+tan(b)+tan(c)=tan(a)tan(b)tan(c)